In an engineering college of 20,000 students, 1,500 like neither their core branches nor other branches. The number of students who like their core branches is 1/4th of the number of students who like other branches. The number of students who like both their core and other branches is 500. The number of students who like only their core branches is
A. 3,300 B. 3,500 C. 1,600 D. 1,500
GATE 2024 · General Aptitude · Venn Diagram · medium
Answer: 3,300 students like only their core branches.
Find the union of both sets: |C union O| = 20,000 - 1,500 = 18,500
Apply inclusion-exclusion to get |C| + |O|: 18,500 = |C| + |O| - 500 => |C| + |O| = 19,000
Use the 1:4 ratio to solve for |C| and |O|: (1/4)|O| + |O| = 19,000 => (5/4)|O| = 19,000 => |O| = 15,200; |C| = 3,800