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In an engineering college of 20,000 students, 1,500 like neither their core branches nor other branches. The number of students who like their core branches is 1/4th of the number of students who like other branches. The number of students who like both their core and other branches is 500. The number of students who like only their core branches is A. 3,300 B. 3,500 C. 1,600 D. 1,500

GATE 2024 · General Aptitude · Venn Diagram · medium

Answer: 3,300 students like only their core branches.

  1. Find the union of both sets: |C union O| = 20,000 - 1,500 = 18,500
  2. Apply inclusion-exclusion to get |C| + |O|: 18,500 = |C| + |O| - 500 => |C| + |O| = 19,000
  3. Use the 1:4 ratio to solve for |C| and |O|: (1/4)|O| + |O| = 19,000 => (5/4)|O| = 19,000 => |O| = 15,200; |C| = 3,800
  4. Find only-core region: only_core = 3,800 - 500 = 3,300