In the figure below, angle DEC = angle BFC. What is angle CBD + angle CAD equal to?
A. angle DEC - angle BFC
B. angle BAD + angle BCF
C. angle BAD + angle BCD
D. angle CBA + angle CAD
Apply exterior angle theorem to triangle with vertex at E: In the relevant triangle, angle DEC = angle CBD + angle BDC (or corresponding combination), linking angle DEC to angle CBD.
Apply exterior angle theorem to triangle with vertex at F: Similarly angle BFC = angle CAD + angle ADF (or corresponding combination), linking angle BFC to angle CAD.
Subtract and use the given equality: Since angle DEC = angle BFC by hypothesis, angle CBD + angle CAD = angle DEC - angle BFC. This is option A. Note: the answer is angle DEC - angle BFC (which numerically equals 0 only if the two are the same value, but as an algebraic expression it is the correct form).