Four archers P, Q, R and S try to hit a bull's eye during a tournament consisting of seven rounds. As illustrated in the figure below, a player receives 10 points for hitting the bull's eye, 5 points for hitting within the inner circle and 1 point for hitting within the outer circle. The final scores received by the players during the tournament are listed in the table below. Round | P | Q | R | S 1 | 1 | 10 | 1 | 10 2 | 5 | 10 | 10 | 1 3 | 1 | 1 | 1 | 5 4 | 10 | 1 | 1 | 5 5 | 1 | 5 | 10 | 10 6 | 5 | 10 | 1 | 5 7 | 10 | 5 | 5 | 1 The most accurate and the most consistent players during the tournament are respectively A. P and S B. Q and S C. Q and R D. R and Q
GATE 2011 · General Aptitude · Tabular Data · medium
Answer: Q is most accurate (total score 42) and S is most consistent (stdev 3.68). Answer: B. Q and S.
- Compute total score for each player: P: 1+5+1+10+1+5+10 = 33 | Q: 10+10+1+1+5+10+5 = 42 | R: 1+10+1+1+10+1+5 = 29 | S: 10+1+5+5+10+5+1 = 37
- Compute mean score for each player: P: 33/7 = 4.71 | Q: 42/7 = 6.00 | R: 29/7 = 4.14 | S: 37/7 = 5.29
- Compute standard deviation to find most consistent player: P: stdev = 4.03 | Q: stdev = 4.08 | R: stdev = 4.26 | S: stdev = 3.68