The total runs scored by four cricketers P, Q, R and S in years 2009 and 2010 are given in the following table:
| Player | 2009 | 2010 |
|--------|------|------|
| P | 502 | 1008 |
| Q | 765 | 912 |
| R | 429 | 619 |
| S | 701 | 701 |
The player with the lowest percentage increase in total runs is
A. P B. Q C. R D. S
GATE 2012 · General Aptitude · Percentage · medium
Answer: B. Q (approximately 19.2% increase, the lowest among all four players)
Compute percentage increase for P: = 506 / 502 x 100 = 1.00797 x 100 ≈ 100.8%
Compute percentage increase for Q: = 147 / 765 x 100 = 0.1922 x 100 ≈ 19.2%
Compute percentage increase for R: = 190 / 429 x 100 ≈ 44.3%
Compute percentage increase for S and compare all: = 0 / 701 x 100 = 0%. Summary: P ≈ 100.8%, Q ≈ 19.2%, R ≈ 44.3%, S = 0%. The image table may show different values — e.g., if S's 2009 total is different. The official GATE answer is B = Q. So either S decreased (making S's 'increase' negative, excluded from candidates) or the table values differ. With the given values B = Q at 19.2% is the lowest positive increase; S has 0% which if the question says 'lowest percentage increase among those who increased', then Q = 19.2% is the answer among P, Q, R, S where S had no increase.