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Four equilateral triangles are used to form a regular closed three-dimensional object by joining along the edges. The angle between any two faces is: A. 30° B. 60° C. 45° D. 90°

GATE 2024 · General Aptitude · Patterns In Three Dimensions · medium

Answer: The dihedral angle of a regular tetrahedron is arccos(1/3) ≈ 70.53°. None of the given options (30°, 60°, 45°, 90°) match this value. The question is marked excluded (X) in the official answer key.

  1. Set up coordinates for a regular tetrahedron: Place the base triangle ABC in the xy-plane. The apex D is above the centroid of ABC at height h = sqrt(2/3). Midpoint M of edge AB = (1/2, 0, 0).
  2. Find vectors perpendicular to the shared edge within each face: These two vectors lie in their respective faces and are perpendicular to edge AB.
  3. Compute the dihedral angle using the dot product: v1 . v2 = (sqrt(3)/2)(sqrt(3)/6) = 3/12 = 1/4. |v1| = sqrt(3)/2. |v2| = sqrt(3/36 + 6/9) = sqrt(1/12 + 2/3) = sqrt(3/4) * (1/sqrt(3)) ... simplifying: cos(theta) = 1/3.