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  1. GATE CS
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  3. General Aptitude

Find the odd one in the following group: A. ALRVX B. EPVZB C. ITZDF D. OYEIK

GATE 2014 · General Aptitude · Odd One Out · medium

Answer: D. OYEIK

  1. Count vowels in each group: ALRVX: A is vowel — count = 1. EPVZB: E is vowel — count = 1. ITZDF: I is vowel — count = 1. OYEIK: O, E, I are vowels — count = 3.
  2. Select the outlier: Three groups share the property of containing exactly one vowel. OYEIK contains three vowels and is therefore the odd one out.