A rectangle has a length L and a width W, where L > W. The width W is increased by 10% for all values of L and W. Which one of the following statements is correct?
A. Perimeter increases by 10%.
B. Length of the diagonals increases by 10%.
C. Area increases by 10%.
D. The rectangle becomes a square.
GATE 2025 · General Aptitude · Mensuration · medium
Answer: When W is increased by 10%, the area increases by exactly 10% for all values of L and W (option C).
Compute new area after 10% increase in W: Original area = LW. New area = L(1.1W) = 1.1LW. Percentage increase = (1.1LW - LW)/LW * 100 = 10%. Area increases by exactly 10% for all L, W.
Check perimeter and diagonal to rule them out: Perimeter increase = 2(0.1W) = 0.2W. Original perimeter = 2(L+W). Percentage = 0.2W / 2(L+W) * 100 = 10W/(L+W) %, which depends on L and W, not always 10%. Diagonal = sqrt(L^2 + 1.21W^2) != 1.1 * sqrt(L^2+W^2) in general. Option D (becomes square) fails since L > W means the new rectangle has L > 1.1W, so L > W' and remains a non-square rectangle.