L, M, and N are waiting in a queue meant for children to enter the zoo. There are 5 children between L and M, and 8 chil...

Question

L, M, and N are waiting in a queue meant for children to enter the zoo. There are 5 children between L and M, and 8 children between M and N. If there are 21 children ahead of N and 40 children behind L, then what is the minimum number of children in the queue?

A. 47
B. 48
C. 60
D. 77

Accepted Answer

The minimum number of children in the queue is 47. Three children L, M, N stand in a queue with given gaps between them and known counts ahead of N and behind L. We want the smallest possible total. The total depends on the order of L, M, N in the queue; placing L closest to the entrance (L-M-N order) minimises the total.

L, M, and N are waiting in a queue meant for children to enter the zoo. There are 5 children between L and M, and 8 children between M and N. If there are 21 children ahead of N and 40 children behind L, then what is the minimum number of children in the queue? A. 47 B. 48 C. 60 D. 77