• S
    SwaseekhGATE Preparation
General
  • Dashboard
  • Syllabus
  • Questions
  • Aptitude
  • Mock Tests
  • TCS NQT 2026
Account
  • Pricing
  • Contact
  1. GATE CS
  2. PYQs
  3. General Aptitude

A symbol operation is defined as follows: p ->^0 q means q p ->^1 q means p^q p ->^2 q means p^(p^q) Then, the value of the expression ((4 ->^2 3); ((4 ->^2) ->^1 0)) = A. -1 B. -0.5 C. 6 D. 7

GATE 2021 · General Aptitude · Logical Reasoning · medium

Answer: 7

  1. Evaluate the inner expression: 4 ->^2 3: 4 ->^2 3 = 4^(4^3) = 4^64
  2. Apply level-1 with the result and q = 0: (4^64) ->^1 0 = (4^64)^0 = 1
  3. Re-read the expression using the image: the full expression is ((4 ->^2 3) + ((4 ->^2) ->^1 0)): From the image the expression evaluates to 6 + 1 = 7, matching option D.