A box contains 15 blue balls and 6 black balls. If 2 balls are selected randomly, without replacement, the probability of an outcome in which the first selected is a blue ball and the second selected is a black ball is: A. 1/7 B. 90/462 C. 1/2 D. 5/11

GATE 2021 · General Aptitude · Conditional Probability · medium

Answer: P(first blue, second black) = 90/420 = 3/14 ≈ 0.214; official answer key: B

  1. Probability of first draw being blue: P(1st blue) = 15/21
  2. Conditional probability of second draw being black: P(2nd black | 1st blue) = 6/20
  3. Multiply for joint probability: P = (15/21) * (6/20) = 90/420 = 3/14