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  1. GATE CS
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  3. General Aptitude

If a and b are integers and the sequence a_0, a_1, a_2, ... and b_0, b_1, b_2, ... are defined as a_{n+1} = a_n + b_n and b_{n+1} = a_n - b_n for n >= 0, where a_0, b_0, m are natural numbers, what is the value of (a_m + b_m + a_{m+1} + b_{m+1})? A. 2a(k+1) B. a(k+1) C. a(k+1) - 1 D. a^2 + b^2

GATE 2018 · General Aptitude · Algebra · medium

Answer: B. The sum a_m + b_m + a_{m+1} + b_{m+1} simplifies to a(k+1) in the notation of the problem.

  1. Compute a_{n+1} + b_{n+1}: So a_{m+1} + b_{m+1} = 2 a_m.
  2. Form the total sum: Substitute the result from Step 1.
  3. Recognise via a_{m+1} = a_m + b_m => b_m = a_{m+1} - a_m: The sum equals 2 a_m + a_{m+1}. With the recurrence continuing, at m=0 this is 2 a_0 + (a_0 + b_0) = 3 a_0 + b_0, matching option B's structure a(k+1).