If matrix X = [[a, a-1], [1-a, 1-a]] and X^2 - X + I = O (I is the identity matrix and O is the zero matrix), then the inverse of X is A. [[1-a, a-1], [a, 1-a]] B. [[1-a, a-1], [a-1, a]] C. I - X D. X has full rank
GATE 2004 · Engineering Mathematics · Matrix · medium
Answer: X^(-1) = I - X = [[1-a, 1-a],[a-1, a]], which corresponds to option B.
- Derive inverse from polynomial relation: From X^2 - X + I = O: X^2 - X = -I => X(X - I) = -I => X(I - X) = I. Therefore X^(-1) = I - X.
- Compute I - X explicitly: I - X = [[1,0],[0,1]] - [[a, a-1],[1-a, 1-a]] = [[1-a, -(a-1)],[-(1-a), 1-(1-a)]] = [[1-a, 1-a],[a-1, a]]