Evaluate the following limit: lim_{x -> 0} ln((x^2 + 1) cos(x)) / x^2
GATE 2024 · Engineering Mathematics · Limits · medium
Answer: 0.5
- Split the logarithm: The limit of the sum equals the sum of limits (both exist).
- Evaluate first part: ln(x^2+1)/x^2: With u = x^2: lim_{x->0} ln(1+x^2)/x^2 = 1.
- Evaluate second part: ln(cos x)/x^2: lim_{x->0} ln(cos x)/x^2 = lim_{x->0} (-x^2/2)/x^2 = -1/2.
- Combine results: The total limit is 1 + (-1/2) = 1/2 = 0.5.