What is the value of lim_{x->0+} x^x ? A. infty B. 0 C. 1 D. Not defined

GATE 2015 · Engineering Mathematics · Limits · medium

Answer: 1

  1. Write as exponential: Need to find L = lim_{x->0+} x * ln(x)
  2. Apply L'Hopital to find the exponent limit: lim_{x->0+} x*ln(x) = lim_{x->0+} (-x) = 0
  3. Exponentiate the limit: Answer = C = 1