Which one of the following functions is continuous at x = 3? A. f(x) = { 2, if x = 3 { x - 1, if x != 3 B. f(x) = { 4, if x = 3 { 8/(x-3), if x != 3 C. f(x) = { x + 3, if x <= 3 { x - 4, if x != 3 D. f(x) = { 1/(x-3), if x != 3
GATE 2013 · Engineering Mathematics · Continuity · medium
Answer: Option A is continuous at x = 3. Answer: A.
- Check Option A: f(3) = 2. For x != 3: f(x) = x - 1, so lim_{x->3} (x - 1) = 3 - 1 = 2. Since lim = f(3) = 2, Option A IS continuous at x = 3.
- Eliminate Options B, C, D: Option B: lim_{x->3} 8/(x-3) does not exist (-> +/-infty). Option C: lim from left = 3+3 = 6, lim from right = 3-4 = -1; left != right so limit doesn't exist. Option D: f(3) is undefined. All three fail continuity at x = 3.