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For each element in a set of size 2n, an unbiased coin is tossed. The 2n coin tosses are independent. An element is chosen if the corresponding coin toss was a head. The probability that exactly n elements are chosen is: A. C(2n,n) / 4^n B. C(2n,n) / 2^n C. 1 / C(2n,n) D. 1 / 2^n

GATE 2006 · Engineering Mathematics · Binomial Distribution · medium

Answer: P(exactly n elements chosen) = C(2n,n) / 4^n. Answer: A.

  1. Identify binomial parameters: Number of trials N = 2n, success probability p = 1/2, desired successes k = n.
  2. Apply binomial probability formula: P(X=n) = C(2n,n) * (1/2)^n * (1/2)^(2n-n) = C(2n,n) * (1/2)^n * (1/2)^n = C(2n,n) * (1/2)^(2n) = C(2n,n) / 2^(2n) = C(2n,n) / 4^n.