Let G be a finite group on 84 elements. The size of a largest possible proper subgroup of G is _____.
GATE 2018 · Discrete Mathematics · Group Theory · medium
Answer: The largest possible proper subgroup has 42 elements.
Subgroup order divides 84: By Lagrange, |H| must be a divisor of 84. The divisors are 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84.
Take the largest proper divisor: The smallest prime factor of 84 is 2, so the largest proper divisor is 84 / 2 = 42. Such a subgroup of index 2 can exist (e.g. in Z_84).