Let G be a simple undirected planar graph on n vertices with e edges. If G is a connected graph, then the number of bounded faces in any embedding of G on the plane is equal to
A. e - n + 1
B. e + n - 1
C. e - n + 2
D. e + n - 2
GATE 2012 · Discrete Mathematics · Graph Planarity · medium
Answer: The number of bounded faces = e - n + 1.
Apply Euler's formula to find total faces: Rearranging: F = E - V + 2 = e - n + 2. This gives all faces including the one unbounded outer face.
Subtract the unbounded face to get bounded faces: Every planar embedding has exactly one unbounded (outer) face. So bounded faces = F - 1 = (e - n + 2) - 1 = e - n + 1.