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  1. GATE CS
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  3. Discrete Mathematics

Let G be a simple undirected planar graph on n vertices with e edges. If G is a connected graph, then the number of bounded faces in any embedding of G on the plane is equal to A. e - n + 1 B. e + n - 1 C. e - n + 2 D. e + n - 2

GATE 2012 · Discrete Mathematics · Graph Planarity · medium

Answer: The number of bounded faces = e - n + 1.

  1. Apply Euler's formula to find total faces: Rearranging: F = E - V + 2 = e - n + 2. This gives all faces including the one unbounded outer face.
  2. Subtract the unbounded face to get bounded faces: Every planar embedding has exactly one unbounded (outer) face. So bounded faces = F - 1 = (e - n + 2) - 1 = e - n + 1.