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  1. GATE CS
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  3. Discrete Mathematics

Consider the undirected graph G defined as follows. The vertices of G are bit strings of length n. We have an edge between vertex u and vertex v if and only if u and v differ in exactly one bit position (in other words, v can be obtained from u by flipping a single bit). The ratio of the chromatic number of G to the diameter of G is A. 1/(n-1) B. 1/n C. 2/n D. 2/(n+1)

GATE 2006 · Discrete Mathematics · Graph Coloring · medium

Answer: C. 2/n

  1. Show Q_n is bipartite => chi = 2: Partition vertices by parity of number of 1-bits: part A = even parity, part B = odd parity. Flipping one bit changes parity, so every edge crosses the partition. Thus Q_n is bipartite and chi(Q_n) = 2.
  2. Compute diameter(Q_n) = n: The vertices 00...0 and 11...1 differ in all n bits. To get from one to the other we must flip each bit individually, requiring exactly n steps. No pair requires more than n steps. So diameter(Q_n) = n.
  3. Form the ratio: chi(Q_n) = 2, diameter(Q_n) = n, so the ratio = 2/n.